Integration

By any chance would any of you know how to integrate
(7x^213x+13)/((x2)(x^22x+3))
Its a question on my homework and I think I’m supposed to integrate by partial fractions, but I can’t seem to get it to work.



The first term is, x2 its coefficient is 1 .
The middle term is, 2x its coefficient is 2 .
The last term, "the constant", is +3Step1 : Multiply the coefficient of the first term by the constant 1 • 3 = 3
Step2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is 2 .
3 + 1 = 4 1 + 3 = 4 1 + 3 = 4 3 + 1 = 4
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factoredEquation at the end of step
1
:STEP
2
:Equation at the end of step
2
:STEP
3
:7x2  13x + 13
Simplify ———————————————————————
(x  2) • (x2  2x + 3)
Trying to factor by splitting the middle term3.1 Factoring 7x2  13x + 13
The first term is, 7x2 its coefficient is 7 .
The middle term is, 13x its coefficient is 13 .
The last term, "the constant", is +13Step1 : Multiply the coefficient of the first term by the constant 7 • 13 = 91
Step2 : Find two factors of 91 whose sum equals the coefficient of the middle term, which is 13 .
91 + 1 = 92 13 + 7 = 20 7 + 13 = 20 1 + 91 = 92 1 + 91 = 92 7 + 13 = 20 13 + 7 = 20 91 + 1 = 92
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factoredFinal result :
7x2  13x + 13
———————————————————————
(x  2) • (x2  2x + 3)Just messing. Got this from Google. No idea what your question actually means.

@terrible2koldman said in Integration:
The first term is, x2 its coefficient is 1 .
The middle term is, 2x its coefficient is 2 .
The last term, "the constant", is +3Step1 : Multiply the coefficient of the first term by the constant 1 • 3 = 3
Step2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is 2 .
3 + 1 = 4 1 + 3 = 4 1 + 3 = 4 3 + 1 = 4
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factoredEquation at the end of step
1
:STEP
2
:Equation at the end of step
2
:STEP
3
:7x2  13x + 13
Simplify ———————————————————————
(x  2) • (x2  2x + 3)
Trying to factor by splitting the middle term3.1 Factoring 7x2  13x + 13
The first term is, 7x2 its coefficient is 7 .
The middle term is, 13x its coefficient is 13 .
The last term, "the constant", is +13Step1 : Multiply the coefficient of the first term by the constant 7 • 13 = 91
Step2 : Find two factors of 91 whose sum equals the coefficient of the middle term, which is 13 .
91 + 1 = 92 13 + 7 = 20 7 + 13 = 20 1 + 91 = 92 1 + 91 = 92 7 + 13 = 20 13 + 7 = 20 91 + 1 = 92
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factoredFinal result :
7x2  13x + 13
———————————————————————
(x  2) • (x2  2x + 3)Just messing. Got this from Google. No idea what your question actually means.



Fuck it, I just skipped it and moved on

@gobles said in Integration:
Fuck it, I just skipped it and moved on
Bro you made @terrible2koldman do all that for no reason

LOBLES

@errolzzz lmao all @terrible2koldman said in his post was an essay on factoring

@sg24 lol I didn’t read shit he said


@errolzzz control C control V
