Integration
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By any chance would any of you know how to integrate
(7x^2-13x+13)/((x-2)(x^2-2x+3))
Its a question on my homework and I think I’m supposed to integrate by partial fractions, but I can’t seem to get it to work.
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The first term is, x2 its coefficient is 1 .
The middle term is, -2x its coefficient is -2 .
The last term, "the constant", is +3Step-1 : Multiply the coefficient of the first term by the constant 1 • 3 = 3
Step-2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is -2 .
-3 + -1 = -4 -1 + -3 = -4 1 + 3 = 4 3 + 1 = 4
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factoredEquation at the end of step
1
:STEP
2
:Equation at the end of step
2
:STEP
3
:7x2 - 13x + 13
Simplify ———————————————————————
(x - 2) • (x2 - 2x + 3)
Trying to factor by splitting the middle term3.1 Factoring 7x2 - 13x + 13
The first term is, 7x2 its coefficient is 7 .
The middle term is, -13x its coefficient is -13 .
The last term, "the constant", is +13Step-1 : Multiply the coefficient of the first term by the constant 7 • 13 = 91
Step-2 : Find two factors of 91 whose sum equals the coefficient of the middle term, which is -13 .
-91 + -1 = -92 -13 + -7 = -20 -7 + -13 = -20 -1 + -91 = -92 1 + 91 = 92 7 + 13 = 20 13 + 7 = 20 91 + 1 = 92
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factoredFinal result :
7x2 - 13x + 13
———————————————————————
(x - 2) • (x2 - 2x + 3)Just messing. Got this from Google. No idea what your question actually means.
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@terrible2koldman said in Integration:
The first term is, x2 its coefficient is 1 .
The middle term is, -2x its coefficient is -2 .
The last term, "the constant", is +3Step-1 : Multiply the coefficient of the first term by the constant 1 • 3 = 3
Step-2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is -2 .
-3 + -1 = -4 -1 + -3 = -4 1 + 3 = 4 3 + 1 = 4
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factoredEquation at the end of step
1
:STEP
2
:Equation at the end of step
2
:STEP
3
:7x2 - 13x + 13
Simplify ———————————————————————
(x - 2) • (x2 - 2x + 3)
Trying to factor by splitting the middle term3.1 Factoring 7x2 - 13x + 13
The first term is, 7x2 its coefficient is 7 .
The middle term is, -13x its coefficient is -13 .
The last term, "the constant", is +13Step-1 : Multiply the coefficient of the first term by the constant 7 • 13 = 91
Step-2 : Find two factors of 91 whose sum equals the coefficient of the middle term, which is -13 .
-91 + -1 = -92 -13 + -7 = -20 -7 + -13 = -20 -1 + -91 = -92 1 + 91 = 92 7 + 13 = 20 13 + 7 = 20 91 + 1 = 92
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factoredFinal result :
7x2 - 13x + 13
———————————————————————
(x - 2) • (x2 - 2x + 3)Just messing. Got this from Google. No idea what your question actually means.
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Fuck it, I just skipped it and moved on
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@gobles said in Integration:
Fuck it, I just skipped it and moved on
Bro you made @terrible2koldman do all that for no reason
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LOBLES
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@errolzzz lmao all @terrible2koldman said in his post was an essay on factoring
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@sg24 lol I didn’t read shit he said
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@errolzzz control C control V
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